Probability Sectional Test JKSSB Class IV by home academy




                             Probability sectional test 
 1.Which of the following can not be the probability of an event? VW

(A)2/ 3

(B) – 1.01

 (C) 12%

 (D) 0.3

2. In a single throw of two dice, the probability of getting the sum 2 is

(A)1/ 9
(B)1/18
(C)1/36
(D)35/36
3. In a simultaneous toss of two coins, the probability of getting one head and one tail is
(A)1/ 3
(B)1 /4
(C)1/ 2
(D)2 /3
 
4. Complete the following statements by filling in blank spaces:

(a) The probability of an event is always greater than or equal to _______ but less than or equal to _______  
(b) The probability of an event that is certain to occur is ________. Such an event is called ________  
(c) The probability of an event which cannot occur is _________. Such an event is __________  
(d) The sum of probabilities of two complementary events is _________  
(e) The sum of probabilities of all the elementary events of an experiment is ______  

5. A card is drawn at random from a well-shuffled deck of 52 cards. Find the probability that this card is a face card.
a. 3/13
b.12/13
c.4/12
d.5/12
6. A coin is tossed two times. What is the probability of getting a head each time?
a.1/2
b.1/3
c.1/4
d.1

7. A card is drawn from a well shuffled deck of 52 playing cards. Find the probability that it is of (i) red colour 
a.1/2
b.1/3
c.1/4
d.1
8. If P(E) = 2/ 7 , what is the probability of ‘not E’?
a.5/7
b.1/7
c.5/2
d.2/5


                                                 Check your answers 

ANSWERS 
1.B
2.C
3.C
4. a- 0,1
    b- sure, certain event
    c- 0, impossible event 
    d- 1
    e- 1
5. Number of all possible outcomes = 52
Number of outcomes favourable to the Event E “a face card
= 3 × 4 = 12  
So, P(a face card) =12/52  
=3/13

6.  Let us write H for Head and T for Tail.
In this expreiment, the possible outcomes will be:
 HH, HT, TH, TT
HH means Head on both the tosses
HT means Head on 1st toss and Tail on 2nd toss.
TH means Tail on 1st toss and Head on 2nd toss.
TT means Tail on both the tosses.
So, the number of possible outcomes = 4
 
Let E be the event “getting head each time”. This means getting head in both the tosses, i.e. HH  
Therefore, P(HH) = 1/ 4  

7. Let E be the event that the card drawn is of red colour.
Number of cards of red colour = 13 + 13 = 26 (diamonds and hearts)
So, the number of favourable outcomes to E = 26
Total number of cards = 52
Thus, P(E) = 26/52 =1/2

8.  P(E) + P(not E) = 1 
P(not E) = 1 – P(E) 
= 1-2/7 =5/7








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